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50 mL NH3 0,1 M + 100 mL NH4Cl 0,5 M
mol NH3 = 50 mL × 0,1 mmol/mL = 5 mmol
mol NH4Cl = 100 mL × 0,5 mmol/mL = 50 mmol
pOH = pKb – logb/gpOH = 5 – log5/50
pOH = 5 – log 0,1
pOH = 5 +1
= 6
pH = 14 – pOH
= 14 – 6
= 8 2. Tentukan pH larutan penyangga yang dibuat dengan mencampurkan 50 mL larutan CH3COOH 0,1 M dengan 50 mL larutan NaCH3COO 0,1 M. (KaCH3COOH = 1,8 × 10–5)
Jawab:
50 mL CH3COOH 0,1 M + 50 mL NaCH3COO 0,1 M
mol CH3COOH = 50 mL × 0,1 mmol/mL= 5 mmol
mol NaCH3COO = 50 mL × 0,1 mmol/mL= 5 mmol
pH = pKa – loga/g
pH = – log 1,8 × 10–5 – log5/5
pH = – log 1,8 × 10–5
pH = 5 – log 1,8
= 4,75
semoga membantu :)