Question

Tolong dong bantu :')
Pakai cara yaaaa

Answer 1

Jawab:

integral tertentu

∫ f(x) dx =  F(x) + C

ₐᵇ∫ f(x) dx = F(b) - F(a)

Penjelasan dengan langkah-langkah:

i)  ₋₁²∫ (3x² + 2x  + 1) dx=

= [x³ + x² + x ]²₋₁

= { 2³- (-1)³} + {2² - (-1)² } + (2 - (-1))

= (8 + 1) + (4 -1) + (2 +1)

= 9 + 3 + 3

= 18

...

ii) ₀²∫ (x² -2x + 1) dx =

= [1/3 x³ - x² + x ]²₀

= 1/3 (2³ -0³) - (2² -0) + (2-0)

= 1/3 (8 - 0) -  (4 - 0) + (2 -0)

= 1/3 (8) - 4  + 2

= 8/3 - 2

= 8/3 - 6/3

= 2/3