Question

Tolong dijawab sekarang
please banget
jika a dan b akar-akar persamaan kuadrat x^2+3x+4=0, persamaan kuadrat baru yang akar-akarnya (a+b)^2 dan (a-b)^2 adalah......

Answer 1

A+b= -b/a = -3/1 = -3
ab=c/a = 4/1 = 4
a-b= √d/a = √-7

x²-(x1+x2)x + x1.x2=0
x²-((a+b)²+(a-b)²)x + (a+b)²(a-b)²=0
x²-(a²+2ab+b²+a²-2ab+b²)x + (-3)²(√-7)²=0
x²-(2a²+2b²)x+63=0
x²-(2(a+b)²-4ab)x+63=0
x²-(2(-3)²-4.4)x+63=0
x²-(18-16)x+63=0
x² - 2x + 63 = 0