tolong dijawab pakai cara yang jelas., Thx
izharulhaq78
![\displaystyle \frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12}{(\sqrt2+\sqrt3)+\sqrt5}\times\frac{(\sqrt2+\sqrt3)-\sqrt5}{(\sqrt2+\sqrt3)-\sqrt5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{(\sqrt2+\sqrt3)^2-(\sqrt5)^2}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{(2+2\sqrt6+3)-5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{5+2\sqrt6-5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{2\sqrt6}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B12%7D%7B%28%5Csqrt2%2B%5Csqrt3%29%2B%5Csqrt5%7D%5Ctimes%5Cfrac%7B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%7D%7B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B12%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B%28%5Csqrt2%2B%5Csqrt3%29%5E2-%28%5Csqrt5%29%5E2%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B12%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B%282%2B2%5Csqrt6%2B3%29-5%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B12%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B5%2B2%5Csqrt6-5%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B12%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B2%5Csqrt6%7D "\displaystyle \frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12}{(\sqrt2+\sqrt3)+\sqrt5}\times\frac{(\sqrt2+\sqrt3)-\sqrt5}{(\sqrt2+\sqrt3)-\sqrt5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{(\sqrt2+\sqrt3)^2-(\sqrt5)^2}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{(2+2\sqrt6+3)-5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{5+2\sqrt6-5}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{12[(\sqrt2+\sqrt3)-\sqrt5]}{2\sqrt6}")
![\displaystyle \frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]}{\sqrt6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]}{\sqrt6}\times\frac{\sqrt6}{\sqrt6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]\sqrt6}{6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=[\sqrt2+\sqrt3-\sqrt5]\sqrt6\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\sqrt{2\times6}+\sqrt{3\times6}-\sqrt{5\times6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\sqrt{4\times3}+\sqrt{9\times2}-\sqrt{30}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B6%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B%5Csqrt6%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B6%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%7D%7B%5Csqrt6%7D%5Ctimes%5Cfrac%7B%5Csqrt6%7D%7B%5Csqrt6%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Cfrac%7B6%5B%28%5Csqrt2%2B%5Csqrt3%29-%5Csqrt5%5D%5Csqrt6%7D%7B6%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5B%5Csqrt2%2B%5Csqrt3-%5Csqrt5%5D%5Csqrt6%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Csqrt%7B2%5Ctimes6%7D%2B%5Csqrt%7B3%5Ctimes6%7D-%5Csqrt%7B5%5Ctimes6%7D%5C%5C%5Cfrac%7B12%7D%7B%5Csqrt2%2B%5Csqrt3%2B%5Csqrt5%7D%3D%5Csqrt%7B4%5Ctimes3%7D%2B%5Csqrt%7B9%5Ctimes2%7D-%5Csqrt%7B30%7D "\displaystyle \frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]}{\sqrt6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]}{\sqrt6}\times\frac{\sqrt6}{\sqrt6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\frac{6[(\sqrt2+\sqrt3)-\sqrt5]\sqrt6}{6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=[\sqrt2+\sqrt3-\sqrt5]\sqrt6\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\sqrt{2\times6}+\sqrt{3\times6}-\sqrt{5\times6}\\\frac{12}{\sqrt2+\sqrt3+\sqrt5}=\sqrt{4\times3}+\sqrt{9\times2}-\sqrt{30}")
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