Question

tolong dijawab lagi buru buru sisa no 6 doang​

Answer 1

Eksponen Fungsi

asimtot datar y = -3

kaˣ ≠ 0

rumus fungsi :

f(x) = y = kaˣ - 3

titik (1,9)

9 = ka¹ - 3

ka = 12 ... (1)

titik (-1,0)

0 = k.a⁻¹ - 3

k/a = 3

k = 3a

12/a = 3a

a² = 4

a = 2

k = 12/a = 12/2 = 6

rumus fungsi eksponen :

f(x) = 6 . 2ˣ - 3