Question

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Answer 1

Verified answer

No. 24
²log²x - ²logx³ - 4 = 0
misalkan 
y = ²logx, maka
y² - 3y - 4 = 0
(y + 1)(y - 4) = 0
y = -1    y = 4

y = -1
²logx = -1
x = 2⁻¹
x = 1/2

y = 4
²logx = 4
x = 2⁴
x = 16

HP = {1/2 , 4}

No. 25
²log(3x - 2) ≤ ²log4
3x - 2 ≤ 4
3x ≤ 6
x ≤ 2
syarat numerus
3x - 2 > 0
3x > 2
x > 2/3
jadi HP = {x| 2/3 < x ≤ 2}

No. 26
(1/2) log(x² + 2x) < -3
(1/2) log(x² + 2x) < (1/2) log(8)
x² + 2x < 8
x² + 2x - 8 < 0
(x + 4)(x - 2) < 0
-4 < x < 2
syart numerus
x² + 2x > 0
x(x + 2) > 0
x < -2  atau  x > 0
iirisan dari kedua syarat
-4 < x < -2   atau   0 < x < 2