Jawaban:
B. T = 40√3 N
Penjelasan:
T.sin 60 + T1.sin 30 = W
T. 0,5√3 + T1. 0,5 = 8. 10
T. 0,5√3 + T1. 0,5 = 80
T√3 + T1 = 160 .................. (1)
T.cos 60 = T1.cos 30
T. 0,5 = T1. 0,5√3
T = T1√3
T1 = T/√3 ............................ (2)
Substitusi persamaan (2) ke persamaan (1)
T√3 + T1 = 160
T√3 + T/√3 = 160
T.( √3 + 1/√3 ) = 160
T.( √3 + √3/3 ) = 160
T. 4√3 / 3 = 160
T = 3. 160 / 4√3 = 120/√3
T = 40√3 N
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Jawaban:
B. T = 40√3 N
Penjelasan:
T.sin 60 + T1.sin 30 = W
T. 0,5√3 + T1. 0,5 = 8. 10
T. 0,5√3 + T1. 0,5 = 80
T√3 + T1 = 160 .................. (1)
T.cos 60 = T1.cos 30
T. 0,5 = T1. 0,5√3
T = T1√3
T1 = T/√3 ............................ (2)
Substitusi persamaan (2) ke persamaan (1)
T√3 + T1 = 160
T√3 + T/√3 = 160
T.( √3 + 1/√3 ) = 160
T.( √3 + √3/3 ) = 160
T. 4√3 / 3 = 160
T = 3. 160 / 4√3 = 120/√3
T = 40√3 N