Tolong dijawab :)
1. ( -5x - 1 ) ² =
2. ( p - 5q ) ² =
3. -a² ( 2a - 6c) =
4. 3ab ( 2a + 2d - 5 ) =
5. 6-5 ( 2p -3q + 4 ) =
Terimakasih ")
1. ( -5x - 1 ) ² =
2. ( p - 5q ) ² =
3. -a² ( 2a - 6c) =
4. 3ab ( 2a + 2d - 5 ) =
5. 6-5 ( 2p -3q + 4 ) =
Terimakasih ")
= 25x^2 + 5x + 5x + 1
= 25^2 + 10x +1
2. (p - 5q) x (p -5q)
= p^2 -5pq -5pq +5q^2
=p^2 -10pq + 5q^2
3. -a^2(2a-6c)
= -2a^3 + 6a^2c
4. 3ab (2a + 2d - 5)
= 6a^2 b + 6abd - 15ab
5. 6-5 ( 2p - 3q +4)
= 6 - 10p + 15q - 20
= -10p + 15q - 14
perkalian dikerjakan lebih dahulu daripada penjumlahan