Question

Tolong Dibantu ya susah + rumusnya ..!!
tentang rumus turunan fungsi

Answer 1

A) f(x) = 3x + 1 ⇒ f'(x) = 3
b) f(x) = (3x+1)² ⇒ f'(x) = 2(3)(3x+1) = 6(x+1)
c) f(x) = (3x+ 1)³ ⇒ f'(x) = 9(3x+1)2
d) f(x) = (3x+1)^4 ⇒f'(x) = 12(3x+1)³
e) f(x) = (3x+1)^10 ⇒ f'(x) = 30(3x+1)^9
f) f(x) = (3x+1)^50 ⇒ f'(x) = 150(3x+1)^49
g) f(x) = (3x+1)^99 ⇒ f'(x) = 297(3x+1)^98