∫_1^2▒〖x√x dx= ∫_1^2▒x^(3/2) 〗=2/5 x^(5/2) ■([email protected]@1)=(2/5×4×√(2))-2/5=(8√2)/5-2/5
c.∫_0^4▒〖x^(-2)=-x^(-1) ■([email protected]@0)〗=-1/4
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∫_1^2▒〖x√x dx= ∫_1^2▒x^(3/2) 〗=2/5 x^(5/2) ■([email protected]@1)=(2/5×4×√(2))-2/5=(8√2)/5-2/5
c.∫_0^4▒〖x^(-2)=-x^(-1) ■([email protected]@0)〗=-1/4