#F
₀³ ∫ (x + 3) dx =
= [¹/₂ x² + 3x ]³₀
= ¹/₂ [3²-0²] + 3[3- 0]
= 9/2 + 9
= 13 ¹/₂
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#F
₀³ ∫ (x + 3) dx =
= [¹/₂ x² + 3x ]³₀
= ¹/₂ [3²-0²] + 3[3- 0]
= 9/2 + 9
= 13 ¹/₂