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No.27y = a^x
melewati (0,1)
1 = a^0 → a∈R
dan melewati (1,3)
3 = a^1 → a = 3
jadi rumus grafiknya : y = 3^x
No. 28
y = ²log(ax + b)
melewati (1,0)
0 = ²log(a + b)
→ a + b = 1 ...............(1)
melewati (2,1)
1 = ²log(2a + b)
→ 2a + b = 2 ............. (2)
melewati (4,2)
2 = ²log(4a + b)
→ 4a + b = 4 ............. (3)
dari (2) dan (3)
4a + b = 4
2a + b = 2
--------------- (-)
2a = 2
a = 1
b = 1
jadi rumus grafik fungsinya
y = ²log(x + 1)