1. B. 2 dan 3
2. c=√20²+15²
c=√400+225
c=√625
c=25 (C)
3. t=12
A = 20
B = 13
a=√20²-12²
a=√400-144
a=√256
a=16
b=√13²-12²
b=√169-144
b=√25
b=5
jarak kapal a dan b = 16-5 = 11 (B)
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1. B. 2 dan 3
2. c=√20²+15²
c=√400+225
c=√625
c=25 (C)
3. t=12
A = 20
B = 13
a=√20²-12²
a=√400-144
a=√256
a=16
b=√13²-12²
b=√169-144
b=√25
b=5
jarak kapal a dan b = 16-5 = 11 (B)