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No. 12misalkan
y = sinx
maka
2y² - 7y + 3 = 0
(2y - 1)(y - 3) = 0
y = 1/2 atau y = 3
y = 3
sinx = 3 (tidak ada x yang memenuhi)
y = 1/2
sinx = 1/2
x = 30
maka
cos30 = (1/2)√3
No. 13
sin²x - cos²x = 0
1 - cos²x - cos²x = 0
1 - 2cos²x = 0
cos²x = 1/2
cosx = (1/2)√2 atau cosx = -(1/2)√2
x = 45 atau x = 135
sin²x - cos²x = 0
sin²x - 1 + sin²x = 0
2 sin²x = 1
sin²x = 1/2
sinx = (1/2)√2 atau sinx = -(1/2)√2
x = 45 , 135 atau sinx = 210
jadi x yang memenuhi adalah x = 135°
No. 14
cosx = 3/5
cosx - cos3x
= cosx - 4 cos³x + 3 cosx
= 4cosx (1 - cos²x)
= 4(3/5) (1 - (3/5)²)
= 12/5 (25/25 - 9/25)
= 12/5 (16/25)
= 192/125
12. y=sin x
maka
2y²-7y+3=0
(2y-1)(y-3)=0
y=1/2 atau y=3
y=3
sin x= 3( x tdk memenuhi)
y=1/2
sin x=1/2
x=30
jadi, cos 30 = 1/2√3 ----- B
13. sin²x-cos²x=0
1-cos²x-cos²x=0
1-2cos²x=0
cos²x=1/2
cos x= 1/2√2 atau cos x= -1/2√2
x= 45°. atau. x= 135°
sin²x-cos²x=0
sin²x-1+sin²x=0
2sin² x = 1
sin²x= 1/2
sin x= 1/2√2 atau sin x= -1/2√2
x= 45°, 135°. atau sin x= 210°
Jadi, x yg memenuhi adalah 135° --- D
14. cos x= 3/5
cos x-cos 3x
= cos x-4 cos³x+3 cos x
= 4 cos x(1-cos²x)
= 4(3/5)(1-(3/5)²)
= 12/5(25/25-9/25)
= 12/5. 16/25
= 192/125 ------ D
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