Question

Tolong bantu kerjakan no 3 dan 5 ya , terimakasih :)

Answer 1

Verified answer

Materi : Trigonometri

No.3
diketahu tinggi segitiga sama kaki, t = p
alas = a = 2q.
sisi miring segitiga, (berdasarkan teorema phytagoras)
c² = (a/2)² + p²
c² = a²/4 + p²
c² = (a² + 4p²)/4
c = (1/2)√(a² + 4p²)

sehingga
sin θ = q/ [(1/2)√(a² + 4p²)]
sin θ = 2q / √(a² + 4p²)

No.5
sinx + √3 . cosx = 1 , 0° ≤ x ≤ 360°

( sinx + √3 . cosx )² = 1²
sin²x + 2√3 . sinx cosx + cos²x = 1
sin²x + cos²x + √3 . sin2x = 1
1 + √3 . sin2x = 1
√3 . sin2x = 0
sin2x = 0
(i)
2x = 0°
x = 0°
(ii)
2x = 180°
x = 90°
(ii)
2x = 360°
x = 180°
dst...

jadi HP = {0°, 90°, 180°, 270°, 360°}