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mol KOH = 50ml x 0,02M = 1mmol
C6H5COOH + KOH ==> C6H5COOK + H2O
1mmol............1mmol.............-..............-
-1mmol.........-1mmol..........+1mmol........+1mmol
-....................-....................1mmol..........1mmol
asam lemah + basa kuat ==> habis bereaksi
itu artinya mengalami hidrolisis basa
maka,
ka asam benzoat = 6,4x10^-5
M = mol/v total = 1mmol/100ml = 0,01 M
[OH-] =
[OH-] =
[OH-] = 1,25x10^-6
pOH = 6-log 1,25
pH = 8+log 1,25