Question

Tolong di bantu ngerjain mtk plis
​

Answer 1

Penjelasan dengan langkah-langkah:

no. 1

limit 1 - sinx/cos²x

x →π/2

limit 1 - sinx/1 - sin²x

x →π/2

limit 1 - sinx/(1 - sinx)(1 + sinx)

x →π/2

limit 1 /(1 + sinx)

x →π/2

= 1/(1 + sinπ/2) = 1/(1 + sin90º)

= 1/(1 + 1)

= 1/2

.

no.2

limit sin2x/cosx

x →π/2

limit 2 sinx cosx/cosx

x →π/2

limit 2 sinx

x →π/2

= 2 sin π/2 = 2 sin90º

= 2

no.3

limit (cosx - cos3x)/(1 - cos2x)

x →0 -2 sin1/2(x + 3x)sin1/2(x - 3x)/(1 - cosx)

limit 2sin2x sinx/(1 - cosx)

x →0

limit 2.2sinx cosx sinx/(1- cosx)

x →0

limit 4sin²x cosx/(1 - cosx)

x →0 4(1 - cos²x)cosx/(1 - cosx)

limit 4(1 - cosx)(1 + cosx)cosx/(1 - cosx)

x →0

limit 4(1 + cosx)cosx

x →0

= 4 (1 + cos0º)cos0º

= 4 (1 + 1)1

= 4 (2)

= 8