#F
Akar persamaan kuadrat
x² + px + 12= 0
x1 + x2 = - b/a = - p
x1 x2 = c/a = 12
x1 x2 = 12 dan x1 = 3x2 maka 3x2. x2 = 12
x2^2 = 12/3 = 4
x2 = 2 atau x 2 = - 2
untuk x2 = 2 --> x1 = 3x2 = 3(2) = 6,maka p = -(x1 +x2) = -(2 + 6) = - 8
untuk x2 = -2 --> x1 = 3x2 = 3(-2) = - 6 , maka p =-( x1 + x2) =-( -2-6)= 8
p adalah 8 atau -8
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#F
Akar persamaan kuadrat
x² + px + 12= 0
x1 + x2 = - b/a = - p
x1 x2 = c/a = 12
x1 x2 = 12 dan x1 = 3x2 maka 3x2. x2 = 12
x2^2 = 12/3 = 4
x2 = 2 atau x 2 = - 2
untuk x2 = 2 --> x1 = 3x2 = 3(2) = 6,maka p = -(x1 +x2) = -(2 + 6) = - 8
untuk x2 = -2 --> x1 = 3x2 = 3(-2) = - 6 , maka p =-( x1 + x2) =-( -2-6)= 8
p adalah 8 atau -8