Question

Tolong bantuin yaa^^

Answer 1

Verified answer

Jari2 ling. kecil = 1/2(28 - (2x7)) = 7
jari2 ling. besar = 1/2 x 28 = 14

setengah keliling ling. besar
= 1/2 ( 2πr)
= πr
= 22/7 x 14
= 44 m

setengah keliling ling. kecil
= 1/2 ( 2πr)
= πr
= 22/7 x 7
= 22 m

keliling kolam
= (2x7) + 44 + 22
= 14 + 44 + 22
= 80 m

pagar 2 kali putaran, maka panjang minimum kawat yang dibutuhkan adalah
= 2 x 80
= 160 m