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Verified answer
S kerucut kecilmisalkan t = 12
s² = 5² + 12²
s² = 25 + 144
s = √169
s = 13
s kerucut besar
s² = 15² + (24 + 12)²
s² = 15² + 36²
s² = 225 + 1296
s² = 1521
s = √1521
s = 39
Lp kertas
= Lp kerucut besar - Lp kerucut kecil
= πrs besar - πrs kecil
= π (15)(39) - π (5)(13)
= 585π - 65π
= 520π