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mol CH3COOH = mol NaOH sehingga menggunakan rumus hidrolisis.
(OH-) = akar Kw : Ka x (mol CH3COO- : V total)
= akar 10^-14:10^-5 x (20:500)
= 2.10^-5,5
pOH = 5,5 - log 2
pH = 8,5 + log 2 (E)
12. dg cara yg sama:
(OH-) = akar 10^-14:5x10^-10 x (0,25:100)
= akar 5x10^-8
=2,2.10^-4
pOH = 4 - log 2,2
pH = 10 + log 2,2 (D)