Jawaban:
mol NH4NO3 = 0.05
massa = 4 gram
Penjelasan:
pH = a - log b
pH garam = 6 - log 5 (pH <7 hidrolisis bersifat asam)
valensi dr asam kuat (asam nitrat = 1)
mol garam NH4NO3 = 0.025 × 2 = 0.05
Mr NH4NO3 = 2×14 + 4 + 3×16 = 80
massa NH4NO3 = mol × Mr = 0.05 × 80 = 4 gram
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Jawaban:
mol NH4NO3 = 0.05
massa = 4 gram
Penjelasan:
pH = a - log b
pH garam = 6 - log 5 (pH <7 hidrolisis bersifat asam)
valensi dr asam kuat (asam nitrat = 1)
mol garam NH4NO3 = 0.025 × 2 = 0.05
Mr NH4NO3 = 2×14 + 4 + 3×16 = 80
massa NH4NO3 = mol × Mr = 0.05 × 80 = 4 gram