Question

Tolong Bantu yah ..... ?

Answer 1

2. y = (1 - (1/2)x^2)^(1/3)
dy/dx = (1/3) (1 - (1/2)x^2)^(-2/3) . -x
=> dy/dx = (x/3) (1 - (x^2 /2))^(-2/3)

3y^2 (dy/dx) + x = 0
=> 3 . (1 - (x^2/2))^(2/3) . (x/3) . (1 - (x^2/2))^(-2/3) + x = 0
=> x + x = 0
=> 2x = 0
=> x = 0

3. y = C1 sin x + C2 cos x
=> dy/dx = C1 cos x - C2 sin x
=> d^2 y/dx^2 = - C1 sin x - C2 cos x

d^2 y/dx^2 + y = 0
=> (-C1 sin x - C2 cos x) + (C1 sin x + C2 cos x) = 0
=> 0 = 0 .......????