" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
f(x) = 2x/(3 - x) = (2x + 0)/(-x + 3)
=> f^-1(x) = (-3x + 0)/(-x - 2) = 3x/(x + 2)
=> f^-1 (1) = 3(1)/(1 + 2) = 3/3 = 1
g^-1(x) = 6/(2 + x)
(f o g)^-1 (1) = (g^-1 o f^-1)(1)
= g^-1(f^-1(1))
= g^-1 (1)
= 6/(2 + 1) = 6/3 = 2