Question

Apa invers dari fungsi berikut f(x) = (x+1)/(x-2)

A. f⁻¹(x) = (1 + x)/(x - 1)
B. f⁻¹(x) = (1 - 2x)/(x - 1)
C. f⁻¹(x) = (1 + 2x)/(x +1)
D. f⁻¹(x) = (1 + 2x)/(x - 1)
E. f⁻¹(x) = (x - 1)/(1 + 2x)

Gunakan cara

Answer 1

F(x) = (x+1)/(x-2)
y =(x+1)/(x-2)
y(x-2)= x+ 1
xy - 2y = x + 1
xy - x = 1 + 2y
x(y -1) = 1 + 2y
x = ( 1 + 2y)/(y - 1)
f⁻¹(x)= (1+ 2x)/(x - 1)