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f(3) = 15 ----> 3a + b = 15
f(-2) = 10 ----> -2a + b = 10
------------------- (-)
5a = 5
a = 1
substitusi,
3a + b = 15
3(1) + b = 15
3 + b = 15
b = 15 - 3
b = 12
b) f(x) = ax + b = x + 12
c) f(7) = 7 + 12 = 19