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a.) f'(x) = 3x + 2 / x - 5
b.) f'(-2) = 3(-2) + 2 / (-2) -5
→ -6 + 2 / -7
→ -4 / -7
= 4/7
no 2
a.) (f o g)'(x) = (g' o f')
→2 (2x - 3) = 4x - 6
kalau dilanjutkan lagi,
→4x = 6
→x = 2 / 3
b.) (g o f)'(x) = (f' o g')
→2 (2x) - 3 = 4x - 3
kalau dilanjutkan lagi,
→4x = 3
→x = 4/3