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ΔH untuk 2 mol = 2 × 181,4 = 362,8 kJ
35. ΔH1 = ΔH3 - ΔH2
= - 790,4 -(-593,8) = - 196,6 kJ
36. Q = m × c × Δt
= 100 × 4,2 × 70
= 29400 J ≈ 29,4 kJ