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1000, 500√2, 500, ...dst. dengan r = 1/√2
1000.(1/√2)ⁿ < 100
log 1000.(1/√2)ⁿ < log 100
log 1000 + log (1/√2)ⁿ < log 100
log (1/√2)ⁿ < log 100 - log 1000
log (1/√2)ⁿ < log (100/1000)
n.log (1/√2) < log (1/10)
n.log (√2) > log 10
n > log 10/√2
n > log 10 + 1/log√2
n > 1 + 1/log√2
sengaja dipanjangin biar puyeng, hahaha