Question

Tolong bantu dijawab kedua nomornya. kalau satu saja gpp​

Answer 1

1. misal massa larutan 1kg, maka massa glukosa = 12% x 1000 gr = 120 gr

mol glukosa = 120 gr/180 = 2/3 mol

molalitas = ⅔ mol/0,88 kg = 0,76 molal

2. misal volume larutan = 1 L

vol HCl = 18,25% x 1 L = 0,1825 L=182,5 ml

massa HCl = 182,5 x 1,1 = 200,75 g

mol HCl = 200,75/(1+35,5) = 5,5 mol

massa air = 81,75 L x 1g/mL=81,75g

mol air = 81,75(2+16)= 4,54 mol

fraksi mol HCl = 5,5/(5,5+4,54)=0,55

fraksi mol H2O = 4,54/10,04 = 0,45