Question

Tolong akuuu pleasee

Answer 1

Jawaban:

D. 2⁻⁴

Penjelasan dengan langkah-langkah:

[(²logx²/4)/²logx] + ²log4x = 4/²logx .kali ²logx

²log(x²/4) + ²logx . ²log4x = 4

²logx² - ²log4 + ²logx(²logx + ²log4) = 4

2²logx - 2 + (²logx)² + 2²logx = 4

(²logx)² + 4(²logx) - 6 = 0

(²logx + 2)² = 6 + 4

²logx + 2 = (+/-)√10

²logx₁ = - 2 + √10

x₁ = 2exp(-2 + √10)

²logx₂ = -2 - √10

x₂ = 2exp(-2 -√10)

x₁ . x₂ = 2exp(-2 + √10) x 2exp(-2 - √10)

x₁ . x₂ = 2exp[(-2 + √10)+(-2 - √10)]

x₁ . x₂ = 2exp(- 4)

x₁ . x₂ = 2⁻⁴............(D)