Question

Tolong ajarin dong no 1 sm 2 pake caranya:((. Makasihh

Answer 1

2). [(3^3) (x^0) (y^-2)/ (2^4) (x^3)(y^-5)]^-1 [(3^3) (x^-1) (y)/(2^2) (x^2)(y^-1)]^2=
[(3/2^-1) (x^-3) (y^3)]^-1 ×[(3/2) (x^-3)(y^2)]^2= (3/2) (x^3) (y^-3) ((3/2)^2) (x^-6) (y^4)
=(27/8) (x^-2)(y)