Question

Rozwiąż równanie

2/(x^2+x)-1/x^2=1/6x

/ -to kreska ułamkowa

Answer 1

(2-x)/(x^2+x)=1/6x

(2-x)/ x^2+x) - 1/6x=0

{[(2x-x)*6x]-x^2-x} / [(x^2+x)*6x]=0

(12x-6x^2-x^2-x) / (6x^3+6x^2)=0

{x(-7x-11)} / [x(6x^2+6x)} = 0

(-7x-11) / (6x^2+6x) =0     /*(6x^2+6x)

(-7x-11)*(6x^2+6x)=0

-42x^3-42x^2-66x^2-66x=0

-42x^3-108x^2-66x=0

2x(-21x^2-54x-33)=0

2x=0

delta=(-54)^2-4*(-21)*(-33)=2916-2772=144

pier z delty=12

x1= (-54-12)/-42=-66/-42=11/7

x2=(-54+12)/-42=-42/-42=1