to jest twierdzenie Pitagorasa..
zad.Oblicz x
reszta w załaczniku
daje naj
x^ - to x do kwadratu, jak coś ;)
a) 8^+8^=x^
64+64=x^
x^=128
x=\sqrt{128}
x=
b)x^+2^=8^
x^+4=64
x^=60
x=2
a) 8²+8²=x²
64+64=x²
x²=128
x=√128
x=8√2
b)
2²+x²=8²
4+x²=64
x²=64-4
x²=60
x=√60
x=√4×√15
x=2√15
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x^ - to x do kwadratu, jak coś ;)
a) 8^+8^=x^
64+64=x^
x^=128
x=\sqrt{128}
x=
b)x^+2^=8^
x^+4=64
x^=60
x=
x=2
a) 8²+8²=x²
64+64=x²
x²=128
x=√128
x=8√2
b)
2²+x²=8²
4+x²=64
x²=64-4
x²=60
x=√60
x=√4×√15
x=2√15