Matematyka z plusem 1
Zad. 6 d / 158
Zapisz , a jak najprostszej postaci.
d) 12b * b - 1 /4 + 14 * b[kwadrat] - 2b/21 - b-b[kwadrat] /3
PS. / to jest kreska ułamkowa
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12b * b - 1 /4 + 14 * b² - 2b/21 - b-b² /3 = 3b(b-1) + 2* b² - 2b/3- b-b² /3=
= 9b(b-1)/3 + 2(b-2b)/3 –( b-b²) /3 = (9b² - 9b +2b² -4b –b - b²)/3 =
= (12b² - 14b)/3 = 4b² - 14/3b = 4b² - 4 i 2/3 b