Diketahui:
AB = 18 cm
DE = 12 cm
CD = 8 cm
BE = 16 cm
Ditanyakan:
AD
Jawab:
AB/DE = AC/CD
AB/DE = (CD+AD)/CD
18/12 = (8+AD)/8
3/2 = (8+AD)/8
8. (3/2) = 8 + AD
12 = 8 + AD
4 = AD
_________________________________________
DETAIL JAWABAN
Mapel: Matematika
Kelas: 9
Materi: Bab 4 - Kesebangunan dan Kekongruenan
Kata kunci: Segitiga, Sebangun
Kode Soal: 2
Kode kategorisasi: 9.2.4
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Diketahui:
AB = 18 cm
DE = 12 cm
CD = 8 cm
BE = 16 cm
Ditanyakan:
AD
Jawab:
AB/DE = AC/CD
AB/DE = (CD+AD)/CD
18/12 = (8+AD)/8
3/2 = (8+AD)/8
8. (3/2) = 8 + AD
12 = 8 + AD
4 = AD
_________________________________________
DETAIL JAWABAN
Mapel: Matematika
Kelas: 9
Materi: Bab 4 - Kesebangunan dan Kekongruenan
Kata kunci: Segitiga, Sebangun
Kode Soal: 2
Kode kategorisasi: 9.2.4