Question

Titik a (10,p),terletak pada garis yg melalui titik b(3,1)dan c (-4,-13),nilai p adalah

Answer 1

(y-(-13) / (1-(-13) = (x - (-4)/(3-(-4)
( y + 13) / 14 = (x + 4) / 7
y + 13 = 14/7 (x+4)
y + 13 = 2 (x+4)
y + 13 = 2x + 8
y = 2x - 5
p = 2(10) - 5
p = 15

Answer 2

y-y1/y2-y1=x-x1/x2-x1
(y-(-13) / (1-(-13) = (x - (-4)/(3-(-4)
( y + 13) / 14 = (x + 4) / 7
y + 13 = 14/7 (x+4)
y + 13 = 2 (x+4)
y + 13 = 2x + 8
y = 2x - 5
p = 2(10) - 5
p = 15