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=5√2
tan theta = 5/(-5) =-1
theta = 135° (kuadran 2)
jd koord polarnya... (5√2, 135°)
r =
r =
r = √50
r = 5√2
y = r.sin α
5 = 5√2 . sin α
sin α =
sin α =
sin α =
α = karena (-5 , 5) berada dikuadra II ---> α =
jadi , (- 5 , 5) =====> (r ,α)
(5√2 , )