Titik (-4, 10) dirotasikan dengan pusat O(0,0) sejauh 60 derajad berlawanan arah putar jarum jam. Hasilnya adalah?
Takamori37
![\left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}\cos 60&-\sin 60\\\sin 60&\cos 60\end{array}\right]\left[\begin{array}{cc}-4\\10\end{array}\right] \\\\ \left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&-\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3}&\frac{1}{2}\\\end{array}\right]\left[\begin{array}{cc}-4\\10\end{array}\right] \\\\ \left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}-2-5\sqrt{3}\\5-2\sqrt{3}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos+60%26-%5Csin+60%5C%5C%5Csin+60%26%5Ccos+60%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%5C%5C10%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B2%7D%26-%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B3%7D%5C%5C%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B3%7D%26%5Cfrac%7B1%7D%7B2%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%5C%5C10%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2-5%5Csqrt%7B3%7D%5C%5C5-2%5Csqrt%7B3%7D%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}\cos 60&-\sin 60\\\sin 60&\cos 60\end{array}\right]\left[\begin{array}{cc}-4\\10\end{array}\right] \\\\ \left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&-\frac{1}{2}\sqrt{3}\\\frac{1}{2}\sqrt{3}&\frac{1}{2}\\\end{array}\right]\left[\begin{array}{cc}-4\\10\end{array}\right] \\\\ \left[\begin{array}{cc}x'\\y'\end{array}\right]=\left[\begin{array}{cc}-2-5\sqrt{3}\\5-2\sqrt{3}\end{array}\right]")
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