Question

Tinggi kerucut=Tinggi tabung=8cm,diameter tabung 12 cm. Luas permukaan bangun diatas?

Answer 1

S = √8²+6²
= 10 cm

Ls kerucut = πrs
= π × 6 × 10
= 60π cm²
Ls tabung = 2πrt
= 2 × π × 6 × 8
= 96π cm²
L alas = πr²
= π × 6²
= 36π cm²
L total = 192π cm² (A)

Answer 2

[ pi * r (r + 2t) ] + [ 2 * pi * r * s ]
[ pi * 6 (6 + 16) ] + [ 2 * pi * 6 * 10 ]
[ pi * 132] + [ pi * 120]
pi * [132 + 120]
pi * 252 = 252 pi cm kuadrat

smoga membantu, klu ga ada jawaban berarti salah soal