Question

Proszę o pomoc!

a) x – 9 = 4x + 1
b) 3(x + 1) = 17 – 4x
c) 9(3x – 2) + 4(5 – 6x) = 0
d) -5x – 2(4 – x) = x
e) [tex]\frac{x-6}{4} + x = \frac{x-3}{2} - \frac{3x}{4}[/tex]

Answer 1

Odpowiedź:

a)

x - 9 = 4x + 1

x - 4x = 1 + 9

- 3x = 10

3x = - 10

x = - 10/3 = - 3 1/3

b)

3(x + 1) = 17 - 4x

3x + 3 = 17 - 4x

3x + 4x = 17 - 3

7x = 14

x = 14/7 = 2

c)

9(3x - 2) + 4(5 - 6x) = 0

27x - 18 + 20 - 24x = 0

3x + 2 = 0

3x = - 2

x = - 2/3

d)

- 5x - 2(4 - x) = x

- 5x - 8 + 2x = x

- 3x - 8 = x

- 3x - x = 8

- 4x = 8

4x = - 8

x = - 8/4 = - 2

e)

(x - 6)/4 + x = (x - 3)/2 - 3x/4  | * 4

x - 6 + 4x = 2(x - 3) - 3x

5x - 6 = 2x - 6 - 3x

5x - 6 = - x - 6

5x + x = - 6 + 6

6x = 0

x = 0

Answer 2

Odpowiedź:

a)x-9=4x+1

x-4x=1+9

-3x=10

x=-10/:3

x=-3 i 1/3

b)3(x+1)=17-4x

3x+3=17-4x

3x+4x=17-3

7x=14/:7

x=2

c)9(3x-2)+4(5-6x)=0

27x-18+20-24x=0

3x=-2/:3

x=-2/3

d)-5x-2(4-x)=x

-5x-8+2x=x

-3x-x=8

-4x=8/:-4

x=-2

Szczegółowe wyjaśnienie: