[tex] \large {2}^{x + 4} = \sqrt[x - 3]{256} [/tex][tex]x = [/tex]︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎.... Question from @callmenasywaa

callmenasywaa @callmenasywaa

September 2022 1 23 Report

[tex] \large {2}^{x + 4} = \sqrt[x - 3]{256} [/tex]
[tex]x = [/tex]
︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎︎ ︎ ︎

Ryzzx

Jawaban:

x = 4

Penjelasan dengan langkah-langkah:

$\begin{aligned}{2}^{x + 4}& = \sqrt[x - 3]{256} \\ \\ {2}^{x + 4} &= \sqrt[x - 3]{ {2}^{8} } \\ \\ { \not2}^{x + 4}& = { \not2}^{ \frac{8}{x - 3} } \\ \\ x + 4 &= \frac{8}{x - 3} \\ \\ (x + 4)(x - 3) &= 8 \\ \\ {x}^{2} - 3x + 4x - 12 - 8& = 0\\ \\ {x}^{2} + x - 20& = 0 \\ \\ (x + 5)(x - 4)&= 0 \\ \\ x = - 5 \: \:& \/\: \:x = 4 \\ \rm \red{Tidak \: Memenuhi}& \: \: \: \: \: \rm\color{blue}{Memenuhi}\end{aligned}$

6 votes Thanks 5

LyraeChan x = -5

LyraeChan 2^(8/(x-3)) = 2^(8/(-5-3)) = 2^(8/-8) = 2^-1

Ryzzx Em iya

LyraeChan eh wait

LyraeChan kurang minus

LyraeChan kayaknya kamu bener, sorry :D

LyraeChan 2^(-5+4) ≠ 2^(-8/(-5-3))

LyraeChan btw emang akar pangkat 1 ada kah :v

Ryzzx Belum pernah liat, tapi kalo [1]\sqrt{{2}^{8}} = {2}^{\frac{8}{1}} = {2}^{8}

Ryzzx kayaknya... // Makasih ilmunya kak :D

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