Odpowiedź:
(3-c)/(a+b)=2 /•(a+b)
3-c=2(a+b)
3-c=2a+2b
-2a-c+3=2b /:2
(-2a-c+3)/2=b
b=(-2a-c+3)/2
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Odpowiedź:
(3-c)/(a+b)=2 /•(a+b)
3-c=2(a+b)
3-c=2a+2b
-2a-c+3=2b /:2
(-2a-c+3)/2=b
b=(-2a-c+3)/2