[tex]u = \frac{64x^4y^2-60x^3y^2}{-4x^3y^2} =\frac{4x^3y^2(16x-15)}{-4x^3y^2}=-16x+15[/tex]
[tex]v = \frac{60xy^3-85x^2y^3}{5xy^3}= \frac{5xy^3(12-17x)}{5xy^3}=12-17x[/tex]
[tex]w = \frac{11x^3y+3x^2y}{-x^2y} =\frac{-x^2y(-11x-3)}{-x^2y} =-11x-3[/tex]
[tex]u + v + w = -16x + 15 +12-17x -11x-3 =24 - 44 x[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[tex]u = \frac{64x^4y^2-60x^3y^2}{-4x^3y^2} =\frac{4x^3y^2(16x-15)}{-4x^3y^2}=-16x+15[/tex]
[tex]v = \frac{60xy^3-85x^2y^3}{5xy^3}= \frac{5xy^3(12-17x)}{5xy^3}=12-17x[/tex]
[tex]w = \frac{11x^3y+3x^2y}{-x^2y} =\frac{-x^2y(-11x-3)}{-x^2y} =-11x-3[/tex]
[tex]u + v + w = -16x + 15 +12-17x -11x-3 =24 - 44 x[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie: