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[H+] = 0,0001 . 2
[H+] = 0,0002
pH = 4 - log 2
pOH = 14 - (4 - log 2)
pOH = 10 + log 2
b) [H+] = M . Valensi Asam
[H+] = 0,05 . 1
[H+] = 0,05
pH = 2 - log 5
pOH = 14 - (2-log5)
pOH = 12 + log 5