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mol as.asetat = 15 ml x 0,1 = 1,5 mmol
mol natrium asetat = 15 x 0,1 = 1,5 mmol
[H+] = Ka . mol as.lemah / mol bs.konjungasi
= 1,8 x 10^-5 x 1,5 mmol / 1,5 mmol
= 1,8 x 10^-5
pH= 5 - log 1,8