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0,1M 0,1M
CN- + H20 -> HCN + OH-
[OH-]= akar kw/ka x [A-]
=akar 10^-14/6,2 10^-10 x 0,1
= akar 0,16 10^-5
=akar 16 10^-6
=4x10^-3
pOH=3-log 4
pH=14-(3-log4)= 11+log 4
pH = 11 + 0,602
pH = 11,602