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v=1500ml
n=0,1mol
Kb=1,8x10⁻⁵
Ditanyakan:pH
Dijawab:
cari M dahulu,
M=n/v
M=0,1/1500ml
M=0.00006666666
M=6,7x10⁻⁴
[H+]=√(Ma.Ka)
[H+]=√((6,7x10⁻⁴).(1,8x10⁻⁵))
[H+]=√1.206-8
[H+]=0.00003464101
[H+]=3,4x10⁻⁵
pH=14-log[H+]
pH=14-5-log3,4
pH=14-5-0,5
pH=8,5