Tentuk pHLarutan dibawah ini.
1.400 ml larutan yang mengandung 148 mg Ca(OH)2.
Tlng dibantu yah,,,:)
1.400 ml larutan yang mengandung 148 mg Ca(OH)2.
Tlng dibantu yah,,,:)
Risep
Mr Ca(OH)₂ = 74
![M= \frac{gr/Mr}{V} \\ \\ = \frac{0,148/74}{0,4} \\ \\ =0,005=5.10^{-3}~M \\ \\ ~[OH^-]=b.M \\ \\ =2. 5.10^{-3}=10.10^{-3}=10^{-2}~M \\ \\ \\ pOH=-log10^{-2}=2 \\ \\ pH=14-pOH= 14-2 = 12](https://tex.z-dn.net/?f=M%3D+%5Cfrac%7Bgr%2FMr%7D%7BV%7D+%5C%5C++%5C%5C+%3D+%5Cfrac%7B0%2C148%2F74%7D%7B0%2C4%7D+%5C%5C++%5C%5C+%3D0%2C005%3D5.10%5E%7B-3%7D%7EM+%5C%5C++%5C%5C+%7E%5BOH%5E-%5D%3Db.M++%5C%5C++%5C%5C+%3D2.+5.10%5E%7B-3%7D%3D10.10%5E%7B-3%7D%3D10%5E%7B-2%7D%7EM+%5C%5C++%5C%5C++%5C%5C+pOH%3D-log10%5E%7B-2%7D%3D2+%5C%5C++%5C%5C+pH%3D14-pOH%3D+14-2+%3D+12 "M= \frac{gr/Mr}{V} \\ \\ = \frac{0,148/74}{0,4} \\ \\ =0,005=5.10^{-3}~M \\ \\ ~[OH^-]=b.M \\ \\ =2. 5.10^{-3}=10.10^{-3}=10^{-2}~M \\ \\ \\ pOH=-log10^{-2}=2 \\ \\ pH=14-pOH= 14-2 = 12")
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