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=10^-3.2
=2.10^-3
POH=3-log 2
=3-0,3
=2,7
PH=14-2,7
=11,3
[OH⁻] = M • Valensi basa
[OH⁻] = 10⁻³ • 2
[OH⁻] = 2 x 10⁻³
pOH = -log [OH⁻]
pOH = -log [2 x 10⁻³]
pOH = 3 - log 2
pOH = 2,7
pH = 14 - pOH
pH = 14 - 2,7
pH = 11,3
Jadi, pH larutannya adalah 11,3